A 5 kg block, resting on a rough horizontal table, is connected by a light inextensible string passing over a light frictionless pulley to another block of mass 2 kg. The 2 kg block hangs vertically as shown in the diagram below
A force of 60 N is applied to the 5 kg block at an angle of 10o to the horizontal, causing the block to accelerate to the left. The coefficient of kinetic friction between the 5 kg block and the surface of the table is 0,5. Ignore the effects of air friction.
1. Draw a labelled free-body diagram showing ALL the forces acting on the 5 kg block. (5)
2. Calculate the magnitude of the:
2.1. Vertical component of the 60 N force (2) 2.2.Horizontal component of the 60 N force (2) 2.3. State Newton’s Second Law of Motion in words. (2)
3. Calculate the magnitude of the:
3.1.Normal force acting on the 5 kg block (2) 3.2.Tension in the string connecting the two blocks (7) [20]
Physical sciences break 1.0 